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I have a Six numbers which are like points that satisfy certain condition.

If the condition is satisfied that point will be given or else 0 will be assigned as points.

I am Storing the points in Six columns as below in table

PointA   PointB    PointC     PointD     PointE      PointF           Sum  
   X       Y         Z          M          N           L         (X+Y+Z+M+N+L)  
   X       0         Z          M          N           0         (X+Y+0+Z+M+0)  
   0       Y         Z          0          N           0         (0+Y+Z+0+N+0)  
   .
   .
   .
   .

In the above case X, Y, Z, M, N, L are unique numbers.

Their sum should be unique column wise

The Point A column can either have X points or Zero, Similarly Point D column can have M points or Zero at its column.Like that every column will have its respective point or zero.

The Sum of X+Y+Z+M+N+L should be unique

In total there are 720 combinations.

How to find numbers at X, Y, Z, M, N, L

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If your six numbers are 1, 2, 4, 8, 16, and 32, all the sums will be distinct. But where do you get 720 combinations? I see only 64. –  Gerry Myerson Nov 7 '12 at 5:08
    
What do you mean by "The Sum of X+Y+Z+M+N+L should be unique"? –  joriki Nov 7 '12 at 5:09
    
No two sum in that sum column should have same value –  user1093513 Nov 7 '12 at 5:12
    
Thank you Great –  user1093513 Nov 7 '12 at 5:26
    
Can you post it as answer I want to accept –  user1093513 Nov 7 '12 at 5:26

1 Answer 1

Comment elevated to answer, at request of OP:

If your six numbers are 1, 2, 4, 8, 16, and 32, all the sums will be distinct. There will be 64 (not 720) of them.

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