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Here is how i calculate the percent of error (Estimated - Actual)/Actual * 100 where the estimated value is obtained by subtracting two different numbers; let us say n1 and n2, so percent of error formula becomes (n1-n2)-Actual/Actual * 100. Now am trying to figure out how much difference does it make to the percent of error if i don't include 4% of n2 in the above equation, considering value of n2 is roughly 3% of n1. Would highly appreciate if anyone can provide some inputs on the same.

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