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Here in Theorem 1 while prooving uniform convergence of


it's said that

$|{\widetilde{X}}^{(2k)}| \leq (\max|ru_0^2|)^k \cdot (\max|\frac{1}{pu_0^2}|)^k \cdot \frac{|b-a|^{2k}}{(2k)!}$

Where did they get factor $\frac{1}{(2k)!}$?

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1 Answer 1

up vote 0 down vote accepted

If we take maximums only of $ru_0^2$ and $\frac{1}{pu_0^2}$ and take integrals correctly, we'll get the answer.

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