# Let $X=N(-2,4)$ be a normal random variable.

Let $X=N(-2,4)$ be a normal random variable.

a) Find $P(-3.3<X<5.2)$

b) Find $P(X^2>49)$

c)What is the type (and parameters) of the random variable $Y=3(2-x)-15$?

For (a) The answer is supposed to be.742, but I keep getting .9958. I know that $P\{y_1 \leq Y \leq y_2\} = P\{Y \leq y_2\} -P\{Y \leq y_1\} = \Phi\left(\frac{y_2-\mu}{\sigma}\right)- \Phi\left(\frac{y_1-\mu}{\sigma}\right)$, but I dont know if I am just making calculation errors. I get $\Phi(\frac{5.2+2}{2})-1+\Phi(\frac{3.3+2}{2})=.9958$. Not sure what I am doing wrong.

For (b) I am a little unsure of what to do. I don't suppose we could take the square root and find $P(X>7)$?

(c) I do not understand. I know its normal with $\mu=-3$ and $\sigma=6$, but how do you get that? I made it so $Y=6-3X-15$. Do you just plug in the values fro $\mu$ and $\sigma$ we are given for $X$ in the beginning and solve it from there?

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Thanks for explaining what you've done so far!

For (a), your error is in turning $\Phi\left(\frac{-3.3+2}{2}\right)$ into $1-\Phi\left(\frac{3.3+2}{2}\right)$. You need to be careful when you switch the minus sign.

Your approach to (b) is almost right, but you need to consider the negative square root as well. $X^2 > 49$ when $X > 7$ OR $X < -7$.

You're on the right track with (c). If $X \sim \operatorname{Normal}(\mu,\sigma^2)$, what is the distribution of $Y = aX + b$?

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@JonathanChristensen-Would it be $a(\mu+\sigma Z)+b$? –  Sprock Nov 2 '12 at 2:24
@Sprock I don't understand what you mean by that... it should be of the form $Y \sim \operatorname{Normal}(\mu^*, \sigma^2^*)$ for some $\mu^*$ and $\sigma^2^*$ defined in terms of the original $\mu$, $\sigma$, $a$, and $b$. –  Jonathan Christensen Nov 2 '12 at 2:26
I think there was an error in what you typed. I didnt read what you typed correctly. The distribution for a normal random variable is $F_Y(x)=\Phi\left(\frac{x+\mu}{\sigma}\right)$. Is that what you were asking? –  Sprock Nov 2 '12 at 2:31
I'm asking: if $X$ is Normal with mean $\mu$ and variance $\sigma^2$, what are the mean and variance of $Y = aX+b$? –  Jonathan Christensen Nov 2 '12 at 2:33
I plugged what is given for X into Y and got $Y=-3-6Z$. So it would be normal(-3,36). –  Sprock Nov 2 '12 at 3:08