Take the 2-minute tour ×
Mathematics Stack Exchange is a question and answer site for people studying math at any level and professionals in related fields. It's 100% free, no registration required.

We have a question to investigate any game between two players that have dice, when the dice are rolled $4$ times what is the probability of getting any number say $4$ or $5$.. note that the highest number is taken. So if a player gets $1,1,1,4$ or $1,2,5,3$ the highest number is taken to go against the other player. So what is the probability of getting the highest number as $1$ which is $1/1296$ and $2$ is $15/1296$, 3 is $56/1296$ but I can't seem to figure out a pattern or to create an equation to get the rest of the probability.

share|improve this question
    
Do you mean that only one of the highest number is taken? what about 1,1,5,5,5. Would then the three 5's be taken? Also, have you considered 1,1,1,1,1? –  yiyi Oct 30 '12 at 11:52

1 Answer 1

Hint: Let $N$ denote that number. Surely one can compute $\mathbb P(N\leqslant n)$ for each $1\leqslant n\leqslant6$, right? Then, $\mathbb P(N=n)=\mathbb P(N\leqslant n)-\mathbb P(N\leqslant n-1)$.

share|improve this answer

Your Answer

 
discard

By posting your answer, you agree to the privacy policy and terms of service.

Not the answer you're looking for? Browse other questions tagged or ask your own question.