Simple but Stuck: How do I find the point of intersection of two lines in Vector Calculus? Given symmetric equations and deriving parametric equations.
Find the point of intersection of the lines L1: x/2 = (y+1)/3 = (z-1)/2 and L2: x/4 = y/5 = z/5
The parametric forms should be $x_1$ = 2t, $y_1$ = -1+3t, $z_1$=1+2t and $x_2$=4t, $y_2$=5t, $z_2$ = 5t
The final solution is (4, 5, 5). It almost looks like someone just grabbed the coefficients from the parametric form of the second line to make the point. Working backwards, how do I get this answer?
In need of the process.
Thank you very much.