# Working out a “Camera” Angle from distance markers

I'm hoping that such a calculation as below will be very easy for the users of this website:

I have a 3D Carousel on my website and a colleague is going to render out some 3D components to sit on the carousel. However, he needs the angle that the "camera" is at on my 3D carousel. The issue is that my 3D carousel is faux 3D, meaning the images at the rear of the carousel do not travel along a Z plane but they just reduce in size to give the impression that they are.

I've added 2 black lines to the carousel and worked out (through a pixel measurement) that there is 243 pixels between the front and back of the carousel. In theory this carousel is perfectly circular.

The radius of the circle is:

r = 2.3 (a number provided by the component to work out the radius)
w = 1000px (the width of the carousel's container)
w / r = 434.782609


I know that there are 243px between the two black lines and that the radius of the circle is 434.78px so how would I work out the angle of the camera using these measurements? I've provided a screenshot to help if I've not explained it properly - on the diagram, I need to find the blue angle:

I need to know how as opposed to just giving the answer because if we decide to change the angle, I need to work out how to reflect this in the 3D render of each component.

If you need a little more information, just comment saying what you need and I'll do my best to trawl through the javascript file to find the answer.

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If I have read it right and the camera is at the center, the distance to the front line is 435-243=192 pixels and the distance to the back line is 435 pixels. So an object on the back line should be 192/435 as large as one on the front line. Taking d as the depth from the front line, the size would be $\frac{192}{d+192}$ of the size on the front line. But I am not sure this was the question.
Then I think the relation I gave works. Basically you have the distance to the front line, $L$ and the depth $D$. So an object at the back is $L+D$ away. Then if $d$ is depth in the frame, the size of the object should be $\frac{L}{L+d}$ as big as if it were at the front. –  Ross Millikan Feb 15 '11 at 14:08
The angle you showed with a blue arc will be $\arctan \frac{H}{D}$ where $H$ is the height above the baseline and $D$ is the horizontal distance to the far edge. Pixels don't come into this. –  Ross Millikan Feb 15 '11 at 14:22