Tell me more ×
Mathematics Stack Exchange is a question and answer site for people studying math at any level and professionals in related fields. It's 100% free, no registration required.
up vote 0 down vote favorite

Carry out Taylor-series deployment of the following function. $$ \begin{align} f(x)&= \operatorname{sec}^2 x \tag{1}\\ g(x)&=\exp \left( -\frac{1}{(1-x)^2} \right) \tag{2} \end{align} $$ I could not be successful.

share|improve this question
1  
I think if you understand Taylor Series at all, you would have been successful or at least you would be able to tell us what you've done so far. Visit Wikipedia's article on Taylor Series and then try again. – OlayinkaSF Oct 26 '12 at 11:10
2  
Can you be successful at doing something about that 33 percent accept rate? – Gerry Myerson Oct 26 '12 at 11:40

Know someone who can answer? Share a link to this question via email, Google+, Twitter, or Facebook.

Your Answer

 
discard

By posting your answer, you agree to the privacy policy and terms of service.

Browse other questions tagged or ask your own question.