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$$\begin{cases} 3x - 2y + z = 8 \\ 4x - y + 3z = -1\\ 5x + y + 2z = -1 \end{cases}$$

Form two equations with y elimanted.

It would be really helpful too see what you guys wrote.

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This strikes me as bizarre: Why not just solve the system of linear equations as usual, and write x=[solution for x] and z=[solution for z] as your two equations? – Douglas S. Stones Oct 26 '12 at 0:56

Hint: just subtract equation $(2)$ from $(3)$ and add to equation $(1)$ to get your $x$.

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You could solve one of the three equations for $y$ (I recommend the second or the third), then substitute that into the other two equations (don't forget to simplify by gathering like terms).

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Add the second and third equations. Then add the first equation to twice the third equation.

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