Mathematics Stack Exchange is a question and answer site for people studying math at any level and professionals in related fields. It's 100% free, no registration required.

Sign up
Here's how it works:
  1. Anybody can ask a question
  2. Anybody can answer
  3. The best answers are voted up and rise to the top

We have the complex valued function: $$f(z)=\sum_{n=0}^{\infty}a_{n}\text{Li}_{-n}(z)\;\;\;\;\;\;\;(\left | z\right |<1)$$ We wish to recover the coefficients $a_{n}$. The only thing I though would work is to try and come up with a function $\phi(n,x)$, such that: $$\int f(z)\phi(n,z)dz=a_{n}$$ or: $$\int\text{Li}_{-n}(z)\phi(m,z)dz=\delta_{nm}$$ but that's about as far as I've gotten. Any help is appreciated. The question is motivated by the following:

Suppose that for some analytic function $g(x)$ we have the values of the function at positive integers, so we can write a Taylor development : $$g(m)=\sum_{n=0}^{\infty}a_{n}m^{n}$$ Now suppose that the following summation is convergent in the open unit disk: $$\sum_{m=1}^{\infty}g(m)z^{m}$$ Using the above Taylor expansion, and the definition of the Polylogarithm function, we have: $$\sum_{m=1}^{\infty}g(m)z^{m}=:f(z)=\sum_{n=0}^{\infty}a_{n}\text{Li}_{-n}(z)\;\;\left | z\right |<1$$ The plan is to recover the coefficients $a_{n}$, and the thus the Taylor expansion of $g(z)$.


By Ramanujan's master theorem, $g(z)$ is given by: $$\frac{\pi}{\sin(\pi s)}g(-s)=\int_{0}^{\infty}\left(f(-x)+g(0)\right)x^{s-1}dx\;\;\;\;(0<\Re(s)<1)$$ However, the function $f(x)$ is not always convergent along the real line, hence the quest for an alternative.

share|cite|improve this question

Your Answer


By posting your answer, you agree to the privacy policy and terms of service.

Browse other questions tagged or ask your own question.