If $A$ and $B$ are two invertible 5*5 matrices, does $B^{T}$$A$ remain invertible?
I cannot find out is there any properties of invertible matrix to my question.
Thank you!
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If $A$ and $B$ are two invertible 5*5 matrices, does $B^{T}$$A$ remain invertible? I cannot find out is there any properties of invertible matrix to my question. Thank you! |
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Of course: $B$ invertible implies $B^T$ invertible, and the product of two matrices is clearly invertible. This is easily seen from these equations: $$BB^{-1}=I\implies (BB^{-1})^T=I\implies (B^{-1})^TB^T=1,$$ and the fact that if $X$ and $Y$ are invertible, $(XY)^{-1}=Y^{-1}X^{-1}$. Perhaps the general properties you should take away are these: $(XY)^T=Y^TX^T$ and $(XY)^{-1}=Y^{-1}X^{-1}$. |
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Yes. $$ \det(B^T\,A)=\det(B^T)\det(A)=\det(B)\det(A)\ne0. $$ Moreover $$ (B^T\,A)^{-1}=A^{-1}(B^{-1})^T. $$ |
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