Tell me more ×
Mathematics Stack Exchange is a question and answer site for people studying math at any level and professionals in related fields. It's 100% free, no registration required.

Let $S$ be a projective surface and $\text{Pic}(S)$ its Picard group, $G$ is some group (in fact, it consists of automorpisms of $\mathbb P^2$). I came across a notation "$\text{Pic}(S)^G$". Could you explain what does it stand for?

share|improve this question
3  
There is a natural action of $G$ on $Pic(S).$ $Pic(S)^G$ is just the $G$-invariant subgroup. I'm not 100% sure of this though. – only Oct 22 '12 at 15:34

Know someone who can answer? Share a link to this question via email, Google+, Twitter, or Facebook.

Your Answer

 
discard

By posting your answer, you agree to the privacy policy and terms of service.

Browse other questions tagged or ask your own question.