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Trying to find the vertices of a ellipse.

This is what I got enter image description here

And so used WolframAlpha just to test it out, this is my third time using it. This is the solution that I got

enter image description here

So as you can see in the implicit plot it shows that in the positive y-axis it is 2.26? would be the answer?

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What is your definition of "vertex" in this context? The ones I can find on the net all imply that the vertices of this ellipse would be its intersection with the $x$ axis. The intersections with the $y$ axis would be "co-vertices". – Henning Makholm Oct 21 '12 at 14:27
I guess the vertices in this case will be the points of the ellipse in the graph – JackyBoi Oct 21 '12 at 14:42
up vote 0 down vote accepted

Because the ellipse is centered at the origin, the verticies occur where one of the coordinates equals 0.

Setting $x=0$: $$49y^2=251$$ $$y = \pm {\sqrt{251} \over 7}$$

Setting $y=0$: $$23x^2 = 251$$ $$x = \pm \sqrt{251 \over 23}$$

Your question asks for the positive x intercept($y=0$). That's $(0,{\sqrt{251} \over 7})$.

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I have no choice but to agree with you, lol. Tks for the clarification. – JackyBoi Oct 22 '12 at 1:27

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