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I use the standard notations. When $x$ is real then by definition $$ I_{\nu}(x)=e^{-\nu\pi i/2}J_{\nu}(ix). $$ I want to define $I_{\nu}$ for complex $z$. Watson (Treatise of the Theory of Bessel Functions, 2nd ed, 3.7, p.77) says it is $$ \begin{cases} I_{\nu}(z)=e^{-\nu\pi i/2}J_{\nu}\left(ze^{\pi i/2}\right), & (-\pi<\arg z\leq\pi/2),\\ I_{\nu}(z)=e^{(3/2)\nu\pi i}J_{\nu}\left(ze^{-(3/2)\pi i}\right), & (\pi/2<\arg z\leq\pi). \end{cases} $$

Q1. $e^{\pi i/2}\neq e^{-(3/2)\pi i}$?

Q2. Why not good to simply put $z$ in place of $x$?

Q3. How was chosen these two cases of argument of $z$? What is the reason?

Watson says "it is usually convenient", but I want mathematical justification.

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Should the different cases have different argument ranges? They both have $-\pi < \arg z \leq \pi/2$ now. –  Antonio Vargas Oct 20 '12 at 15:30
    
@AntonioVargas thanks, it was a typo, I corrected it. –  vesszabo Oct 23 '12 at 19:39
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