$\left(\frac{y}{y-1}\right)^y = \left( 1 + \frac 1{y-1}\right)^y$ Can someone please help me with this? I cannot understand how they made this step! Banging my head over this for far too long now :(

Thank you Lukas

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We have $\frac y{y-1} = \frac{y-1+1}{y-1} = \frac{y-1}{y-1} + \frac 1{y-1} = 1 + \frac 1{y-1}.$

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Thank you very much Martini! Perfect! –  Lukas Arvidsson Oct 19 '12 at 15:32
$$\frac{y}{y-1} = \frac{y-1+1}{y-1} = \frac{y-1}{y-1} + \frac{1}{y-1} = 1+ \frac{1}{y-1}$$