# How to show that $\left(\frac{y}{y-1}\right)^y = \left( 1 + \frac 1{y-1}\right)^y$

I need to show

$\left(\frac{y}{y-1}\right)^y = \left( 1 + \frac 1{y-1}\right)^y$

I cannot understand how they made this step! Can someone explain how this works?

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We have $\frac y{y-1} = \frac{y-1+1}{y-1} = \frac{y-1}{y-1} + \frac 1{y-1} = 1 + \frac 1{y-1}.$

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Thank you very much Martini! Perfect! – Lukas Arvidsson Oct 19 '12 at 15:32

$$\frac{y}{y-1} = \frac{y-1+1}{y-1} = \frac{y-1}{y-1} + \frac{1}{y-1} = 1+ \frac{1}{y-1}$$

There's the line of thought I use. You add and subtract one (adds up to zero, so it's allowed), then you rearrange everything to get the final result.

Edit: crud, not quick enough...

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Thank you very much, i had totally forgotten about that "method". But now it is clear! – Lukas Arvidsson Oct 19 '12 at 15:33
This is the same @martini did (+1). :) – Babak S. Oct 19 '12 at 16:30