Take the 2-minute tour ×
Mathematics Stack Exchange is a question and answer site for people studying math at any level and professionals in related fields. It's 100% free, no registration required.

I want a short proof of Kuratowski's lemma (about maximal chains).

Does proving Kuratowski's lemma need first prove Zorn lemma?

I am writing a book in which I claim that the reader needs to know only basic set theory in order to understand it. For this reason I need a short proof of Kuratowski's lemma, for the readers of my book.

share|improve this question
    
Well, the proof using ZL seems to be straightforward, see PlanetMath. –  Martin Sleziak Oct 18 '12 at 12:34
    
There are elementary proofs, but they all provide little insight. The best proof is IMHO by transfinite recursion: Add elements until you cannot add elements anymore without the set not being a chain.. –  Michael Greinecker Oct 18 '12 at 12:34
2  
Zorn's lemma is basic set theory. –  Chris Eagle Oct 18 '12 at 12:36
1  
There are easy, elementary proofs of (KL implies ZL) and (ZL implies KL). Thus, proving KL can't be significantly easier than proving ZL. –  Chris Eagle Oct 18 '12 at 12:39
add comment

1 Answer

The answer depends entirely on what you consider elementary set theory. Kuratowski’s lemma is equivalent to the axiom of choice, which is independent of the usual ZF axioms of set theory. Thus, you can’t prove it in ZF; you can either assume it as an axiom, or assume one of the other equivalents of the axiom of choice and derive it from that.

If you intend to assume the axiom of choice and derive Kuratowski’s lemma from that, you will need to use transfinite recursion at some point. If you take this approach, your proof will be intuitively nice, as Michael Greinecker noted in the comments, but it will be technically a bit difficult if you mean to do it very rigorously.

If, on the other hand, you intend to assume Zorn’s lemma as a basic axiom, you can prove Kuratowski’s lemma almost trivially, but at the cost of assuming a much less intuitively satisfying equivalent of the axiom of choice. An intermediate alternative is to take the well-ordering principle as an axiom.

If you’re going to want more than one of the various equivalent statements later, you might as well spend a little extra time introducing them. As I said elsewhere, brevity is not always a good thing when you’re trying to explain something.

share|improve this answer
add comment

Your Answer

 
discard

By posting your answer, you agree to the privacy policy and terms of service.

Not the answer you're looking for? Browse other questions tagged or ask your own question.