How would one go about proving the following. Any ideas as to where to start?
For any integer n, the floor of n/2 equals n/2 if n is even and (n-1)/2 if n is odd.
[n/2] = n/2 if n = even [n/2] = (n-1)/2 if n = odd
Working through it, I try to initially set n = 2n for the even case but am stuck on how to show its a floor...