Assume minimum number of sample points as 0
i.e P(A)=0 and P(B)=0
this implies P(A and B)=0
but then A and B become disjoint and thus by above proof they cannot be independent
Assume the minimum number of sample points to be 1
i.e P(A)=1 and P(B)=0
implies P(A and B)=0
i.e A and B are disjoint
|||ly P(A)=0 and P(B)=1 cannot be mutually independent
let P(A)=1 and P(B)=1 i.e they refer to same sample point
then A and B refer to the same event and hence cannot be mutually independent
Assume the minimum number of sample points to be 2
e.g let us toss a biased coin(coin that always shows a head) and an unbiased coin one after the other.
thus sample points are HH and HT
let A refer to showing a head on biased coin
let B refer to showing a head on unbiased one
P(A)=1 and P(B)=1/2
P(A and B)=1/2 = P(A)*P(B)
and thus they are independent.
thus minimum number of points in a sample space if there are two events A and B that are independent of each other is 2.