Tell me more ×
Mathematics Stack Exchange is a question and answer site for people studying math at any level and professionals in related fields. It's 100% free, no registration required.

Let $f, g: X \rightarrow \mathbb{R}$ be continuous functions, where ($X, \tau$) is a topological space and $\mathbb{R}$ is given the standard topology.

a)Show that the function $f \cdot g : X \rightarrow \mathbb{R}$,defined by $(f \cdot g)(x) = f(x)g(x)$

is continuous.

b)Let $h: X \setminus \{x \in X | g(x) = 0\}\rightarrow \mathbb{R}$ be defined by $h(x) = \frac{f(x)}{g(x)}$

Show that $h$ is continuous.

share|improve this question
Is this homework? Please tag accordingly to get more helpful answers. – Ittay Weiss Oct 16 '12 at 20:57

2 Answers

up vote 2 down vote accepted

The central fact is that the operations $$p:\ {\mathbb R}^2\to{\mathbb R},\quad (x,y)\mapsto x\cdot y$$ and similarly $q:\ (x,y)\mapsto {\displaystyle{x\over y}}$ are continuous where defined and that $$h:\ X\to{\mathbb R}^2,\quad x\mapsto\bigl(f(x),g(x)\bigr)$$ is continuous if $f$ and $g$ are continuous.

It follows that $f\cdot g=p\circ h$ is continuous, and similarly for ${\displaystyle{f\over g}}$.

share|improve this answer

(a) Given $a \in X$, as $f$ is continuous for all sequencie $(x_k) \subset X$, where $x_k \to a $ implies $f(x_k) \to f(a)$, like wise $g(x_k) \to g(a)$. As $(x_k) \subset \mathbb{R}$ we have $$f(x_k)g(x_k) \to f(a)g(a), \ x_k \to a.$$ Therefore $f.g(x) \to f.g(a), \ x \to a.$

share|improve this answer
Well the sequence def of continuity works for metric spaces, here we have topological space. I guess that this is a problem, isnt it? – user2084063 Feb 19 at 11:15
+1 because if one replaces "sequence" with "net" the proof is valid. – CutieKrait Mar 14 at 11:09

Your Answer

 
discard

By posting your answer, you agree to the privacy policy and terms of service.

Not the answer you're looking for? Browse other questions tagged or ask your own question.