# About the continuity of the Fourier transform.

If $x^{\alpha} g \in L^1 ( \Bbb R^n)$ for $| \alpha | \leqslant k$, then how can I prove that its Fourier transform $$\mathscr{F} g \in C^k ( \Bbb R^n) ?$$ Here $\alpha$ is a multi-index.

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Hint: Integration by parts. However, I think you'll only find that weak derivatives exist, not strong derivatives. –  Christopher A. Wong Oct 15 '12 at 21:09

You know that if $g\in L^{1}(\mathbb{R}^{n})$ then $\mathscr{F}g\in C(\mathbb{R}^{n})$
Now try to prove this formula: $$x^{\alpha}D^{\beta}_{x}\mathscr{F}f(x)=(-1)^{|\beta|}\mathscr{F}(D^{\alpha}x^{\beta}f)(x)$$