Take the 2-minute tour ×
Mathematics Stack Exchange is a question and answer site for people studying math at any level and professionals in related fields. It's 100% free, no registration required.

This question may sound weird. I'm attending a course of growth economics and our professor taught us some simple rules about difference equations. He taught us two different methods, but didn't tell us when to use the first one and when to use the other one. In the first case, when we have something like

$y_t = y_{t-1} + h$ we solve with $y_t = y_0 + th$

and when

$y_t=b y_{t-1}$ we get $y_t =b^t y_0$

So when $\boldsymbol{y_t = y_{t-1} + 6} $, the solution is $y_t = y_0 + 6t$

But when we have something like $\boldsymbol{y_{t+1} = 2y_t - 2}$

we have to solve it with a more complex procedure, finding the general and the particular integrals.

I don't understand if the difference between the two "exercises". Is it just in the fact that the second one has a coefficient attached to $y_t$?

Thank you in advance!

share|improve this question
add comment

1 Answer

up vote 1 down vote accepted

I think you can find the answer to your question in this document (p. 222 and following pages)

http://www.cimt.plymouth.ac.uk/projects/mepres/alevel/discrete_ch14.pdf

share|improve this answer
    
Could you add some more context beyond a link? –  Daniel Rust Jul 23 '13 at 14:24
add comment

Your Answer

 
discard

By posting your answer, you agree to the privacy policy and terms of service.

Not the answer you're looking for? Browse other questions tagged or ask your own question.