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Does $ \dfrac{-2}{2\sqrt{u}} $ equal $-\sqrt{u}$ or $-\dfrac{1}{\sqrt{u}}$

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Perhaps the interesting thing here is to ask why would anyone think the square root in the denominator would/should/could "jump" to the numerator? – DonAntonio Oct 13 '12 at 10:53

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$$\frac{-2}{2\sqrt{u}} = \frac{-1}{\sqrt{u}} = - \frac{1}{\sqrt{u}}$$

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