After how many years the deposited sum of K-euros will triple itself if the interest percentage of capitalization is 12%, the capitalization is annual.
Tell me more
×
Mathematics Stack Exchange is a question and answer site for
people studying math at any level and professionals in related fields. It's 100% free, no registration required.
|
$$K\cdot 1.12^n=3K \implies n = \frac{\log(3)}{\log(1.12)} \approx 9.6 \text{ years}$$ |
||||
|
|
|
If you multiply it by $1 + 0.12$ every year for $t$ years, you've multiplied it by $1.12^t$, so you want $1.12^t=3$. That implies $\log(1.12^t)=\log 3$, so $t\log1.12=\log3$. Solve that for $t$. |
|||
|
|
