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Im not sure how to tackle this exactly would i use quotient rule?


Kinda lost at this one maybe someone can quide me in the right path

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If you can show your attempt at the quotient rule and explain the problem you're having using it, then we could show you what you're missing. – Hurkyl Oct 8 '12 at 23:34
up vote 3 down vote accepted

Many options. One is to rewrite as $-12s^{-5}$.

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Oh so just by moving the fraction up there turning it into a $s^-5?$ right – soniccool Oct 8 '12 at 23:29
$1/(a^b)$ is the same thing as $a^{-b}$. Note that I haven't taken the derivative --- I've just rewritten the function in a way that might make it easy to take the derivative (without needing to use the quotient rule). – Gerry Myerson Oct 8 '12 at 23:33
Okay i got it! ! – soniccool Oct 8 '12 at 23:37
Now that you've gotten it, you should try actually using the quotient rule, which says that the derivative of $f/g$ is $(g\cdot f'-f\cdot g')/g^2$. The wonderful thing about these rules is that the two different methods give the same result. – Lubin Oct 8 '12 at 23:39

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