# Finding the unit vectors parallel to a tangent line

This is the solution to the problem. However, I dont understand how they got to the part that says "and the parallel vector is i+4j..". What does this mean and how did they derive that?

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For any real number $m$, the vector $(1,m)$ determines a line of slope $m$ through the origin: simply note that the line through $(0,0)$ and $(1,m)$ has rise $m$ and run $1$.
In this case, your $m=4$, so the vector $(1,4) = 1i + 4j = i+4j$ is a vector of the appropriate slope, hence parallel to the tangent.
@mohabitar: That it makes things easy! Or, that it is pretty much the easiest number to divide by. The vector $(x,y)$, with $x\neq 0$, determines a line of slope $\frac{y}{x}$. So you want to find any $x$ and $y$ with $\frac{y}{x}=m$. You can certainly find others, but isn't the simplest thing to take $x=1$? –  Arturo Magidin Feb 7 '11 at 1:58