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I know theres a summation series for basic $a^x$. Like $2^{x-1}$ is summed by $2^x-1$. Then how would you sum $5\times2^{x-1}$?

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Hint: Distributive law –  Thomas Andrews Oct 5 '12 at 4:01
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You would distribute out the $5$ and get $$\sum_{i=1}^x 5\cdot 2^{i-1}=5\sum_{1=1}^x 2^{i-1}=5( 2^x-1)$$

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@GerryMyerson: I thought of that after I went to bed. My only excuse is that I followed OP's notation. Fixed and thanks. –  Ross Millikan Oct 5 '12 at 13:05
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