How to programmatically find the inverse of a 2x2 matrix (mod 26).

I'm trying to create a hill cipher utility. One feature I want is to be able to compute the key if you have the plaintext and ciphertext.

$C$ = ciphertext matrix ($2\times 2$), $P$ = plaintext matrix $\left(2\times\frac{N}{2}\right)$, $K$ = key ($2\times 2$).

$$PK = C$$

So if I have $C$ and $P$, then $K = P^{-1}C$. How do I best find $P^{-1}$?

EDIT: It is important to note that this is all mod $26$. Sorry.

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See also this related question on StackOverflow. –  Douglas S. Stones Oct 5 '12 at 2:16

You could use the direct formula for $2 \times 2$:
$$\pmatrix{a & b\\ c & d}^{-1} = \dfrac{1}{ad-bc}\pmatrix{d & -b\\-c & a}$$
Yes, it would have to be the modular inverse, the extended gcd algorithm would be one way to do it. In your example, 25 is its own inverse, another example is $3^{-1} \equiv 9 (mod 26)$ since $3 \times 9 = 27 \equiv 1 (mod 26)$ –  adam W Oct 5 '12 at 2:09
Yes! Also, consider that $2$ and $13$ and any multiples (basically just even numbers and the number $13$) do not have modular inverses. –  adam W Oct 5 '12 at 2:19