The Monty Hall problem
I’m looking for the better explanation to the solution of this riddle, because I always struggle to get people to accept the ones I know.
There are three cards facing down on a table and one of them is the 2 of clubs.
You are given the chance to point one of them to guess the 2 of clubs (1/3 chances of getting it right).
With the card you choose still facing down, the card dealer pick one of the other remaining two cards, and face it up, showing to you that it’s not the 2 of clubs.
You are now given the opportunity to change you card selection between the two that still facing down. What should you do to get the maximum probability of wining, keep your initial choice or change it to the other card? Why?