Take the 2-minute tour ×
Mathematics Stack Exchange is a question and answer site for people studying math at any level and professionals in related fields. It's 100% free, no registration required.

Given 1 roll in a game of craps, a win is if, the sum of outcomes on a fair pair of dice is 7 or 11, otherwise you are said to crap-out . Compute the probability of a win on just 1 roll? Im second guessing myself on my answer

share|improve this question
add comment

2 Answers

up vote 1 down vote accepted

I believe you will be able to obtain the answer by adding the probability of rolling a 7 with two dice and the probability of rolling an 11 with 2 dice.

Therefore: $P_7 + P_{11}= \frac{1}{6}+ \frac{1}{18}$ $= \frac{2}{9}$

share|improve this answer
    
Thank you so much –  kimj Sep 30 '12 at 23:34
add comment

Imagine you have a red die and a green die. Each can come up $6$ ways, so there are $6^2=36$ possible rolls. How many sum to $7$? How many sum to $11$?

share|improve this answer
    
3/36+ 1/36= 4/36...reduced fraction 2/9....Thank you so much. –  kimj Sep 30 '12 at 23:34
add comment

Your Answer

 
discard

By posting your answer, you agree to the privacy policy and terms of service.

Not the answer you're looking for? Browse other questions tagged or ask your own question.