A veterinarian has 5 dogs and 4 cats available for adoption. Four of the dogs are brown and 1 is gray.Three of the cats are browm and 1 is gray. Jena selects two animals at random. Find the probability that at least 1 is a cat given that at least 1 is gray.
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If I understood correctly we have to have 1 cat and 1 animal has to be gray. Lets count good possibilities p.
These two options are distinct. So all good p = 11 and the probability is 11/72