Sign up ×
Mathematics Stack Exchange is a question and answer site for people studying math at any level and professionals in related fields. It's 100% free, no registration required.

I am unsure how to find the error bounds for Hermite interpolation. I have some kind of idea but I have a feeling that I am going wrong somewhere.

$f(x)=3xe^x-e^{2x}$ with my x-values being 1 and 1.05

My hermite interpolating polynomial is: $H(x)=.7657893864+1.5313578773(x-1)-2.770468386(x-1)^2-4.83859508(x-1)^2(x-1.05)$

Error Bound: $\large{f^{n+1}(\xi)\over (n+1)!}*(x-x_0)(x-x_1)...(x-n)$

$$\large{f^3 (\xi) \over 3!}(x-1)^2(x-1.5)$$


We must find the maximum point of this cubic function which is at $(1.0333,1.8518463*10^{-5})$ $$\large{f^3 (\xi) \over 3!}*1.8518463*10^{-5}$$ Am I on the correct path and How would I continue from here?

share|cite|improve this question

Your Answer


By posting your answer, you agree to the privacy policy and terms of service.

Browse other questions tagged or ask your own question.