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Could someone explain why

$$\lim\limits_{x\to-\infty}\log [1 + \exp(-x)]+x=0$$

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Excuse me, I didn't understand your question. – HipsterMathematician Sep 22 '12 at 21:27
i want to know how we got this result – alan Sep 22 '12 at 21:32
Which result are you talking about? – Nils Matthes Sep 22 '12 at 21:34
Limit[Log [1 + E^(-x)] + x, x -> -Infinity] = 0 – alan Sep 22 '12 at 21:35
The first version of the question was dreadful but, after the revision by @PeterTamaroff, this became a bona fide mathematical question. Hence I disagree with the decision to close as not a real question. – Did Sep 30 '12 at 10:06

$$\log(1+\mathrm e^{-x})+x=\log((1+\mathrm e^{-x})\cdot\mathrm e^{x})=\log(\mathrm e^{x}+1)\underset{x\to-\infty}{\longrightarrow}\log(0+1)=0$$

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I think you may have meant the exponential function, which is Exp[-x].


Do you see why it is infinity, just by inspection?

The exponential approaches zero, Log[1] is zero and the remaining terms grows to infinity.

If this is acceptable, you should accept the answer.

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yes exponential function – alan Sep 22 '12 at 21:37

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