If there are $26$ available capital letters and $6$ available numbers $0$ to $9$ to complete a $6$ "digit" combination (a license plate for example) what is the formula for calculating the number of possible combinations? I am not a math major nor do i understand all the symbols you guys use, the simplest equation or maybe just the answer will be appreciated... THANKS!!
You multiply the choices at each position. If each position can have all $36$ possibilities, you have $36^6=2,176,782,336$ plates available. If you require that the first three positions be letters and last three be numbers (a common pattern) it is $26^3\cdot 10^3=17,576,000$