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If there are $26$ available capital letters and $6$ available numbers $0$ to $9$ to complete a $6$ "digit" combination (a license plate for example) what is the formula for calculating the number of possible combinations? I am not a math major nor do i understand all the symbols you guys use, the simplest equation or maybe just the answer will be appreciated... THANKS!!

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1 Answer 1

You multiply the choices at each position. If each position can have all $36$ possibilities, you have $36^6=2,176,782,336$ plates available. If you require that the first three positions be letters and last three be numbers (a common pattern) it is $26^3\cdot 10^3=17,576,000$

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