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I came across this matrix riddle a couple of weeks ago and I haven't figured it out.

  1. You have a known $10\times10$ matrix $A$, which is symmetric.
  2. For some unknown transformation matrix $T$, you have the relation that $\Lambda = T^TAT$.
    $\Lambda$ is a diagonal matrix and $T$ is not necessarily orthogonal, so this isn't the normal diagonalization problem.
  3. You have another relation for $T$: $J = TJT^T$, where $J$ is a $10\times10$ matrix such that the top right $5\times5$ block is an identity matrix and the bottom left $5\times5$ block is $-I$ (identity matrix).

How do you find what $T$ and $\Lambda$ are? Obviously $T$ is $10\times10$.

Using the two relations, I got the following equation: $J\Lambda = T^{-1}JAT$.

I don't if that helps.


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It doesn't help to have a 17 percent accept rate. –  Gerry Myerson Sep 17 '12 at 5:47
Are the top left and bottom right blocks of $J$ unknown? –  joriki Sep 17 '12 at 7:30
They are all zeros. –  user34801 Sep 17 '12 at 18:26
@Gerry Myerson: I'm sorry, but I actually didn't know that you could accept answers until you and someone else pointed it out to me. –  user34801 Sep 17 '12 at 18:31
Have you checked the $2\times2$ case, $J=\pmatrix{1&0\cr0&-1\cr}$? Maybe small enough to write everything out explicitly to see what's going on, and then see what applies to the $10\times10$. –  Gerry Myerson Sep 18 '12 at 1:22
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