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Hey guys I am unsure how to find the error bound. Use the langrange interpolating polynomial of degree 3 or less and four digit chopping arithmetic to approximate $\cos(.750)$ using the following values. Find an error bound for the approximation.

$\cos(.698)=.7661, \cos(.733)=.7432, \cos(.768)=.7193, \cos(.803)=.6946$

The actual value of $\cos(.750)=.7317$
I used Lagrange interpolating polynomials and got .6915 Now how would I find the error bound? The formula for the error bound is: $\large{f^{n+1}(\xi(x)) \over (n+1)!}*(x-x_0)(x-x_1)...(x-x_n)$

In this case the formula would be: $\large{f^{4}(\xi(x)) \over (4)!}*(x-.698)(x-.733)(x-.768)(x-.803)$ Just not sure how to continue from here

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1 Answer 1

Error bound is also called Margin of Error. EB= CV*SE. where: EB is error bound CV is critical value and SE is Standard error.

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