$ \left(\dfrac{a^{2}b^{-{\color{red}3}}}{x^{-{\color{red}3}}y^{2}}\right)^{3}\left(\dfrac{x^{-2}b^{-1}}{a^{\frac{{\color{red}3}}{{\color{red}4}}}y^{\frac{1}{3}}}\right) $
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What you want is probably $$a^{5 \frac{1}{4}} b^{-10} x^{7} y^{-6 \frac{1}{3}}$$ You just have to add up the powers... Looks very much like high school homework. |
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Use the laws of exponents: You can bring the cube on the first fraction inside using $(c^d)^e=c^{de}$. Then pull all the terms in denominators upstairs using $\frac 1a=a^{-1}$. Then combine the powers of the same variable using $c^dc^e=c^{(d+e)}$ |
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