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Has anyone found a good formula to convert a depth of fluid to a volume remaining in a tank for a cylindrical tank laying horizontal? (with or without half sphere end caps) Much Thanks!

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migrated from Sep 6 '12 at 15:41

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Is this a mathematical or Mathematica-related question? If it is generally about math, this question should be migrated... – Yves Klett Sep 6 '12 at 15:33
The version without half sphere end caps was asked here. – Américo Tavares Sep 6 '12 at 16:11
(Pi*r^2)/2 + Sqrt[h]*(h - r)*Sqrt[-h + 2*r] + r^2*ArcTan[(h - r)/(Sqrt[h]*Sqrt[-h + 2*r])] – belisarius has settled Sep 6 '12 at 16:14
Not a duplicate: This tank has half-sphere end caps. – Lord_Farin Oct 24 '13 at 10:30

1 Answer 1

You could see Wikipedia on the area of a circular segment and multiply by the length. If you want spherical end caps, see Wikipedia on a spherical cap. The two ends together make a sphere.

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