Mathematics Stack Exchange is a question and answer site for people studying math at any level and professionals in related fields. Join them; it only takes a minute:

Sign up
Here's how it works:
  1. Anybody can ask a question
  2. Anybody can answer
  3. The best answers are voted up and rise to the top

Has anyone found a good formula to convert a depth of fluid to a volume remaining in a tank for a cylindrical tank laying horizontal? (with or without half sphere end caps) Much Thanks!

share|cite|improve this question

migrated from mathematica.stackexchange.com Sep 6 '12 at 15:41

This question came from our site for users of Mathematica.

    
Is this a mathematical or Mathematica-related question? If it is generally about math, this question should be migrated... – Yves Klett Sep 6 '12 at 15:33
    
The version without half sphere end caps was asked here. – Américo Tavares Sep 6 '12 at 16:11
    
(Pi*r^2)/2 + Sqrt[h]*(h - r)*Sqrt[-h + 2*r] + r^2*ArcTan[(h - r)/(Sqrt[h]*Sqrt[-h + 2*r])] – Dr. belisarius Sep 6 '12 at 16:14
    
Not a duplicate: This tank has half-sphere end caps. – Lord_Farin Oct 24 '13 at 10:30

You could see Wikipedia on the area of a circular segment and multiply by the length. If you want spherical end caps, see Wikipedia on a spherical cap. The two ends together make a sphere.

share|cite|improve this answer

Your Answer

 
discard

By posting your answer, you agree to the privacy policy and terms of service.