Perimeter of an ellipse

Question

How can I calculate the perimeter of an ellipse? What is the general method of finding out the perimeter of any closed curve?

Answer 1

For general closed curve(preferably loop), perimeter=$\int_0^{2\pi}rd\theta$ where (r,$\theta$) represents polar coordinates.

In ellipse, $r=\sqrt {a^2\cos^2\theta+b^2\sin^2\theta}$

So, perimeter of ellipse = $\int_0^{2\pi}\sqrt {a^2\cos^2\theta+b^2\sin^2\theta}d\theta$

I don't know if closed form for the above integral exists or not, but even if it doesn't have a closed form , you can use numerical methods to compute this definite integral.

Generally, people use an approximate formula for arc length of ellipse = $2\pi\sqrt{\frac{a^2+b^2}{2}}$

you can also visit this link : http://pages.pacificcoast.net/~cazelais/250a/ellipse-length.pdf

Answer 2

I do not know if that's what you wanted, but the only general method is to calculate the length of the curve. If we have a ellipse equation:

$\frac{x^2}{a^2}+\frac{y^2}{b^2}=1$

with parametric representation:

$x=a \cos t, \ \ y=b \sin t, \ \ \ t\in [0,2\pi]$

the length of the curve is calculated knowing:

$x'=-a \sin t, \ \ y'=b \cos t, \ \ \ t\in [0,2\pi]$

and is (see Arc length)

$\int_{0}^{2 \pi} \sqrt{a^{2}\sin^{2}t+b^{2}\cos^{2} t} dt$

this integral can not be solved in closed form. There are various approximations (they take advantage of the power series) that you can see in this link

ellipse

Answer 3

For any ellipse, its perimeter is given by $p=2πa(1-(\frac{1}{2})^2ε^2-{(\frac{1.3}{2.4})}^2\frac{ε^4}{3}-\cdots)$