I am trying to solve this. I already got the answer but my doubt is if I am doing it right.
There are two solutions for $x$ in the equation, to 2 decimal places. What is the value of the greater of the two solutions?
$$a|x+b|+c = 0$$ $a = 10$, $b = 4$ and $c = -46$
my solution's as follows:
Step 1, Substitute the values:
$$10|x+4|-46 = 0$$
Step 2, solve:
$$10|x+4| = 46$$
$$|x+4| = +4.6$$ or $$|x+4| = -4.6$$
Hence $x$ can be $x = 0.60$ or $x = -8.60$.
is that the correct way of doing it?