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how does $$1+\cos2\theta = (2-\sqrt2)/2$$ give you $-\sqrt2/2$?

i get that you subtract 1 from the left side, but how does doing so on the right give you $-\sqrt2/2$?

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Well, if you want to subtract two numbers when one or both of them are fractions, it's a good idea to make them both into fractions with the same denominator. You can then just subtract the numerators. So have a think about what the number 1 would look like if you had to write it as a fraction with 2 as the denominator. –  user22805 Sep 2 '12 at 5:51
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${2-\sqrt2\over2}={2\over2}-{\sqrt2\over2}=1-{\sqrt2\over2}$. –  Gerry Myerson Sep 2 '12 at 5:51
    
So obvious, I can't believe I didn't see that. Gerry thanks a lot. –  Kyle H Sep 2 '12 at 5:55
    
An equation like $1+\cos\theta=(2-\sqrt{2})/2$ can only give "true" or "false", but not a number $\ldots$ –  Christian Blatter Sep 2 '12 at 11:40
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1 Answer 1

up vote 2 down vote accepted

$1+\cos 2\theta=\frac{2-\sqrt 2}{2}=\frac{2}{2}-\frac{\sqrt 2}{2}=1-\frac{\sqrt 2}{(\sqrt 2)^2}=1-\frac{1}{\sqrt 2}$

$\implies 1+\cos 2\theta=1-\frac{1}{\sqrt 2}\implies \cos 2\theta=-\frac{1}{\sqrt 2}$

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