Take the 2-minute tour ×
Mathematics Stack Exchange is a question and answer site for people studying math at any level and professionals in related fields. It's 100% free, no registration required.

The examples $C_n, D_n, A_4, S_4, A_5$ are the first nice examples of groups to relate with 2-D and 3-D Euclidean geometry. These groups can be investigated by studying action on sphere as described in M. Artin's book on Algebra. Next, Fano plane is another nice object to relate the simple group of order 168 with (finite) geometry. Then, by considering the double cover $SU(2)$of $SO(3)$, we get few more finite groups (called double/binary groups). The good references to study these groups and geometry (as far as I saw) are

Geometries and Groups (Viacheslav, Shafarevich)

Groups: A path to Geometry (R. P. Burn)

Groups and Geometry (P.M. Neumann, etc.)

On Quaternions and Octonions (Conway, Smith).

Can one suggest more references (books, notes, articles) to see more finite groups with geometry?

share|improve this question
    
Iterated wreath products often appear in symmetry groups of rooted trees. For example, $D_4 \simeq \mathbb{Z}_2 \wr \mathbb{Z}_2$ is such a symmetry group. –  Seirios Aug 22 '12 at 8:20
    
The Geometry of the Classical Groups by D.E. Taylor. –  j.p. Aug 23 '12 at 6:38

2 Answers 2

You might enjoy "Finite Reflection Groups" by Benson and Grove.

share|improve this answer

Non-euclidean tessellations and their groups by William Magnus. For example, the author shows that $T^*(\ell,m,n)=\langle a,b,c | (ab)^{\ell}=(bc)^m=(ac)^n=1 \rangle$ is the group of symmetries of a triangular tessellation on the plan if $\displaystyle \frac{1}{\ell}+ \frac{1}{m} + \frac{1}{n} =1$, on the hyperbolic plane if $\displaystyle \frac{1}{\ell}+ \frac{1}{m} + \frac{1}{n} <1$ or on the sphere if $\displaystyle \frac{1}{\ell}+ \frac{1}{m}+ \frac{1}{n}>1$. Thus, $T^*(\ell,m,n)$ is finite iff $\displaystyle \frac{1}{\ell}+ \frac{1}{m}+ \frac{1}{n}>1$!

share|improve this answer

Your Answer

 
discard

By posting your answer, you agree to the privacy policy and terms of service.

Not the answer you're looking for? Browse other questions tagged or ask your own question.