Graph $f(x)=\ln x+2$ And find all intercepts and asymptotes.
I know exactly how the graph looks and I have a sketch in front of me. Now, for the intercepts, $x$-int=$-1$ and $y$-int$=-\infty+2$ which I'm guessing is just $-\infty$ because adding $2$ wouldn't make much of a difference on that level. So, I have my intercepts (correct me if they are wrong please) now for the asymptotes. For vertical: $\log(x)+2 \rightarrow \infty$ as $x\rightarrow 0$ thus making the vertical asymptote $0$. And for horizontal, it has to do with when $y \rightarrow\pm\infty$. But how do I find this. (The inly reason I know that the vertical asymptote is $0$ is because it's a $\log x$ function moved up $2$ units).