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I'm defining an arc by calling a function like this: arc(x, y, radius*2, radius*2, start, end);

x: center x.
y: center y.
radius*2: width.
radius*2: height.
start: start angle in radians or degrees.
end: end angle in radians or degrees.

And now I need to "close" the arc by drawing two lines, both from the center of the arc, to the start and end point of the arc.

How do I find the start and end points?

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You know the parametric equations for a circle? –  J. M. Aug 20 '12 at 13:51
    
No I don't think so. –  Gautama Dude Aug 20 '12 at 14:01
2  
Well... you have some reading to do then!. If you get stuck come back with your sticking point. –  rschwieb Aug 20 '12 at 14:27
    
If you have different values for width and height, you have an ellipse, not a circle. Why is radius*2 repeated in the argument list? –  Ross Millikan Aug 20 '12 at 14:33
    
Are you working in GeoGebra? –  Sigur Aug 20 '12 at 14:45
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1 Answer

After reading http://en.wikipedia.org/wiki/Equation_of_a_circle#Equations as suggested by @rschwieb I came up with the following:

s_x = x+radius*Math.cos(startAngle*Math.PI);
s_y = y+radius*Math.sin(startAngle*Math.PI);
e_x = x+radius*Math.cos(endAngle*Math.PI);
e_y = y+radius*Math.sin(endAngle*Math.PI);
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If your angles are in radians, you do not need the Math.PI factor. If your angles are in degrees, then you will need a factor of Math.PI/180 instead. –  robjohn Aug 22 '12 at 19:16
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