Take the 2-minute tour ×
Mathematics Stack Exchange is a question and answer site for people studying math at any level and professionals in related fields. It's 100% free, no registration required.

I'm looking for some way of understanding the Martin Axiom for some $\kappa$ in an intuitive way. I know that the motivation is the Baire Category Theorem, however is there any other way of thinking about this axiom?

Thanks in advance.

share|improve this question
    
This might be useful, even though it will probably not satisfy yo completely: math.stackexchange.com/q/99188/21674 –  Michael Greinecker Aug 16 '12 at 22:51
    
@Yamauti What's wrong with the Baire Category Theorem analogy? –  azarel Aug 16 '12 at 23:26
    
@azarel In some way, when I see Baire Category Theorem I fell much more confortable than dealing with an abstract poset with a bizarre topology. Maybe a combinatorial way of thinking or probably some picture of the poset structure would be of great help (not a combitarial equivalence of this axiom, since the equivalences of MA are, at least for me, not less trivial, but much more harder to understand with MA (in the sense that to understand the equivalence you will have to understand the demonstration in a intuitive way) –  Yamauti Aug 17 '12 at 15:44
1  
@Yamauti: How familiar are you with forcing? –  Asaf Karagila Aug 17 '12 at 15:50
    
@AsafKaragila I just know the basic about forcing. I don´t know things like iterated forcing or the more general form of forcing (without models, as Shoenfield does in his book). –  Yamauti Aug 17 '12 at 21:22

1 Answer 1

up vote 2 down vote accepted

Since you mentioned in your comment that you're not familiar with iterated forcing, I'll try to explain a different aspect of $MA$, which I still hope can shed some light on this subject.

One way of understanding $MA_{\aleph_1}$ is in the general context of forcing axioms. If $\mathbb P$ is a forcing notion such that each $p\in \mathbb P$ has two incompatible members above it, then for every generic set $G\subseteq \mathbb P$, $G\notin V$. However, we would still like to find "quite generic" sets in the universe. More formally, let $\Gamma$ be a class of forcing notions. We say that $MA(\Gamma)$ holds if for every $\mathbb{P}\in \Gamma$ and a collection $\{I_{\alpha} : \alpha<\omega_1\}$ of dense sets, there is a filter $G$ on $\mathbb{P}$ that intersects all the $I_{\alpha}$. It turns out that we can prove the consistency of $MA(\Gamma)$ for non pathological classses of forcing notions. In this case, $MA_{\aleph_1}$ is simply $MA(\Gamma)$ when $\Gamma$ is the collection of c.c.c. forcing notions. By enlarging $\Gamma$ we obtain stronger forcing axioms, such as $PFA$ for the class of proper forcing notions and $MM$ for the class of stationary set preserving forcing notions. In this view, $MA_{\aleph_1}$ is just one level in a hierarchy of axioms that imply the existence of sufficiently generic sets.

share|improve this answer
    
I should really collect all your hundred of accounts and ask them to be merged... :-) –  Asaf Karagila Aug 18 '12 at 19:57

Your Answer

 
discard

By posting your answer, you agree to the privacy policy and terms of service.

Not the answer you're looking for? Browse other questions tagged or ask your own question.