Take the 2-minute tour ×
Mathematics Stack Exchange is a question and answer site for people studying math at any level and professionals in related fields. It's 100% free, no registration required.

Lets say you have a chemical solution $A$ that has a ratio of $4:1$ of water to some chemical substance, and a solution $B$ that has a ratio of $9:1$ of water to some other chemical substance.

If you combine the same amount of each solution, the resulting solution is not in a ratio of $6.5 : 1$ (the average), but is instead $5.6666 : 1$.

Can someone help me understand why one cant just average the two ratios if the same amount of solution is added together? For some reason its just not clicking.

share|improve this question
add comment

3 Answers

up vote 3 down vote accepted

Take 10x litre of each solution, so we are adding 8x & 9x litre of water (not 8x litre each), 2x & x litre of that chemical(not 2x or x litre each).

So, total water = (8x + 9x) litre = 17x litre and total chemical=(2x + x) litre = 3x litre.

So, the resultant ratio is $\frac{17}{3}=5.666...$

Clearly, when we are adding the same amount of the solutions, the same amount of water (or the chemical) are not added.

Trivially, we could take average, only if we had added same amount of water (or the chemical) separately.

Let us assume that the ratio of water and the chemical be a:b in the first solution and c:d in the second.

Let's take (a+b)x litre of the 1st solution and (c+d)y litre of the second.

So, water taken = (ax + cy) litre and the chemical taken = (bx + dy) litre.

If $\frac{ax+cy}{bx+dy}=\frac{\frac{a+c}{2}}{\frac{b+d}{2}}$


So if bc=ad=>c:d=a:b (i.e., if the ratios of water & the chemical are same), the ratio of water & the chemical will be the ratio of their average for any values of x,y i.e., we can mix the solutions in any ratio.

Here is this question $a=4,b=1,c=9,d=1=>bc-ad=1.9-4.1≠0=>x=y$

So, we need to take (4+1)x and (9+1)x litres of the solutions, respectively to make the ratio of water and the chemical as the ratio of their average.

share|improve this answer
add comment

As you are taking equal amount of each chemical, for your procedure to work, you need to make sum of terms in ratios equal keeping the ratios unchanged. For example here, for chemical A ratio is $4:1\implies $ sum is $5$, so you need to write ratio of chemical B as $4.5:0.5$, then mixing equal amount of each chemical gives ratio of mixture $=\frac{4+4.5}{1+0.5}=5.6666...$

share|improve this answer
add comment

Keep in mind that it's the ratio of water/chemical.

If you have 4:1 water/chemical for solution A and 9:1 water/chemical for solution B, then solution A is 4/5 water and solution B is 9/10 water. Then if you mix together $x$ units of solution A with $x$ units of solution B, you get $4x/5 + 9x/10 = 17x/10$ units of water per $2x$ units of mixture. Thus, you know that $17/20$ of the mixture is water, so the ratio of water/chemical is $17/3 = 5.666\ldots$.

share|improve this answer
add comment

Your Answer


By posting your answer, you agree to the privacy policy and terms of service.

Not the answer you're looking for? Browse other questions tagged or ask your own question.