# Converting imperial-based equations to metric

I have the following equation:

$\frac{n\times2.2046}2\times0.0284130625$

to: convert kg to lbs, divide by $2$, then convert the result from oz to L

is there a shortcut to do this without the conversion to imperial?

yeah, I know this is probably a very elementary question, math has never been my strong suit.

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The kilogram is a unit of mass, while the liter is a unit of volume... –  Ｊ. Ｍ. Aug 9 '12 at 13:40
What are you actually trying to calculate? –  celtschk Aug 9 '12 at 13:48
this is a nutrition thing: basic amount of water before factoring in environment, etc = half of body weight (in pounds) in oz of water per day, hence the mass to volume conversion. –  bee.catt Aug 9 '12 at 13:53
"this is a nutrition thing: basic amount of water before factoring in environment" - should've mentioned that to begin with. Where did you obtain this formula? –  Ｊ. Ｍ. Aug 9 '12 at 13:56
sorry, J.M., I should have explained that better. If you mean the equation for lbs:oz, I have found it in various places, couldn't give you an exact reference without searching it out again, it gives a similar result to 1L:1000cal. As for the equation above, it was what I was able to come up with myself to take a stored metric value, perform the imperial equation, and return a metric result. –  bee.catt Aug 9 '12 at 14:04
$1$ pound is $16$ ounces, and $1$ litre of water has mass very, very close to a kilogram (apparently only about 0.999975 kg). So you should be able to multiply the mass in kg by $\frac{1}{32} = \frac{1}{2} * \frac{1}{16}$ to get effectively the same result.