# What is the difference between empirical distribution , classical probability and axiomatic definition

Can you tell me what is the difference between empirical distribution and classical probability? My teacher has told me that when we take limit empirical distribution will get a constant value

$$P(A)=\lim_{N\rightarrow\infty}f(A)=\lim_{N\rightarrow \infty}\frac{N(A)}{N}= \mathrm{constant}$$

where $F(A)$ is the frequency ratio, $N(A)$ is the number of times Event $A$ is found to occur and $N$ is the number of times random experiment repeated

But classical probability will give

$$P(A)=\lim_{n\rightarrow \infty }\frac{m}{n}= 0$$

but what I know of limit is like this

$$\lim_{x\rightarrow\infty}\frac{1}{x}=0$$

Then how come empirical distribution is giving a constant instead of zero?

And last can you explain what and why we use axiomatic definition?

Advance thanks for your help... I am a newb to probability statistics

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The difference between the classical definition and the empirical are similar to the difference between a theory and an experiment in physics. The theory is developed in an abstract (perfect) way while the experiments are practical observations. The same happens with probability.

In the classic definition of probability of an event you will assign a probability to an event based on abstract thinking. For example : what is the probability of getting the result 2 when perform the calculation $\frac{2x}{2}$, where $x=1,2,\dots,100$? There are $n=100$ possible outcomes but the result 2 will only occur once, so $m=1$. This is because we can write the relation as $\frac{2x}{2}=\frac{2}{2}x=x$, so only $x=2$ gives the right result. In this case we will say that the probability is $1/100$. So, in classical probability you think of the space of the outcomes and try to find an abstract reason to assign the probability (we used mathematics logic to came up with the number of possibilities and the one of outcomes).

In the empirical definition, on the other hand, you don't think, you just do experiments and count. So, to solve the last problem , you will do as many calculations as you can from the 100 possible and count how many times you get 2. For example, if you perform this experiment on the first 10 numbers (N=10)you will get only once the result of 2 , (N(A)=1), so your estimate for the probability will be $\frac{1}{10}$. This is not the right probability, but more experiments you do, better the estimate is.Closer you get to exhausting the number of possible outcomes closer you are to the true probability.

Now, everything is fine when the possible outcomes are a in finite number. The classical approach gives the right result but might require complex thinking, while the empirical approach gives without effort an estimate that will improve with the number of "measurements/experiments".

What about when you have an infinite number of outcomes? For example: what is the probability of selecting the number 6 from a box with all the natural numbers from 1 to 100? What if in the box there are the numbers to n=10.000, or n=10000000000.......0? The classic definition has an answer for you. Since 6 is unique, the probabilities are $\frac{1}{100}$, $\frac{1}{10.000}$ and $\frac{1}{10000000....0}$. The last probability is almost zero, which is the case "$P(A)=\lim_{n\rightarrow \infty}\frac{m}{n}=0$".

The empirical definition will never give you a good answer for this question since it won't ever be able to exhaust the possible outcomes. If in N tries the experimenter doesn't select the number 6, then the probability will be indeed $\frac{N(A)}{N}=\frac{0}{N}=0$, but the results was "correct" only by the chance of the experimenter. Instead, if she selects 6 at the beginning of the experiment, the result is $\frac{N(A)}{N}=\frac{1}{N}$ and the experimenter will get closer to the result only after a tremendous number of experiments. We need to notice here that there is never in the goal of the empiricist to reach infinity ($N\rightarrow\infty$)since she is always working with finite samples, she doesn't look for perfect knowledge but for useful approximations.

Another example : what is the probability of tails when flipping a fair coin? The classic approach will argue that the probability of "tails" in one flip is $1/2$ because there are only two possible outcomes and "tails" is one of them $\frac{m}{n}=\frac{1}{2}$. The empiricist will do N experiments and will count how many times A=tails occurs and finds $\frac{N(tails)}{N}$. This will always give her a constant since N is always a finite number of experiments.

Apart from the discourse whether the empiricist wants to reach infinity, by the law of large numbers the average result from a large number of experiments will get closer to the expected value of the phenomenon studies. By this law $\lim_{N\rightarrow\infty}\frac{N(A)}{N}$ will $converge$ (not equal) to the expected probability of the event A, which is a constant.

The axiomatic definitions are conceived in an abstract perfect manner such that no mathematical contradiction can occur. This makes possible building a solid theory by using mathematical logic. The probability axioms where first proposed by Kolmogorov and can be found here http://en.wikipedia.org/wiki/Probability_axioms.

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The empirical distribution is the distribution of the sample or sample estimate.

In your context the distribution here $p=$ # of successes over number of trials and $1-p=$ number of failures over number of trials of the empirical distribution for your estimate of the binomial proportion parameter. It converges in probability to a constant as the sample size goes to infinity.

By classic probability the person just means ordinary probability theory. But if $m=N(A)$ and $n=N$ the convergence is not to $0$. It converges to the constant and $m$ goes to infinity with $n$. If $m$ is a constant or converges to a finite limit then $m/n$ will go to $0$ as $n$ goes to infinity. There should be no contradictory result.

To discuss axiomatic definition you need to put the term in context.

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