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I've developed the following algebraic equation which could probably be simplified further. Also, I need it reorganized to solve for x and Y (in terms of A, x, and Y. Not looking for a numerical answer to x or Y). Any takers?

$$ A=0.0193(\frac{x+0.05}{0.05})^2+0.0876(\frac{x+0.05}{0.05})+(\frac{Y}{0.2}(0.75+0.028(\frac{x+0.05}{0.05})))+1.356 $$

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It indeed can be simplified. For example $\dfrac{x + 0.05}{0.05} = 20x + 1.$ But what do you mean by "solve" for $x, Y.$ We have 1 equation in 3 unknowns: $x, Y, A.$ –  user2468 Aug 1 '12 at 16:11
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1 Answer 1

up vote 2 down vote accepted

$A = x(8.106x + 2.8Y + 17.906) + 3.89Y + 2.2513$

$\large Y = \frac{10A - 81.06x^2 - 176.06x - 22.513}{28x + 38.9}$

$x$ is not at all pretty, so I'll just link you to it.

I hope that's what you wanted.

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Thanks guys! Let me check those out. –  Etienne Aug 1 '12 at 17:29
    
I must have confused my formula above somehow. Here it is in plain text: A=(0.0193*((x+0.05)/0.05)^2)+(0.0876*((x+0.05)/0.05))+SUM(1.356,(Y/0.2*(0.75+(0.‌​028*((x+0.05)/0.05))))) –  Etienne Aug 1 '12 at 17:47
    
Your simplification comes to A = 2.2513 when I plug in x = 0 and Y = 0, whereas mine comes to A = 1.46 –  Etienne Aug 1 '12 at 17:49
    
Yep, I mistyped 0.876 when it should be 0.0876. My apologies! –  Etienne Aug 1 '12 at 17:51
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