# Some Simple Algebra

\begin{align*} x &= \frac 12 js + \frac 12 is \\\ y &= \frac 14 is - \frac 14 js \end{align*}

How can I find a \begin{align*} i &= \\\ j &= \end{align*} conversion of this?

Edit:

I am not happy with the moderaters assumption on my syntax.

x = (j * s / 2) + (i * s / 2)
y = (i * s / 4) - (j * s / 4)


is the proper format.

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–  joriki Jul 28 '12 at 9:51
SimpleRookie, x = (j * s / 2) + (i * s / 2) is exactly the same as $x = \frac{js}{2} + \frac{is}{2}.$ –  user2468 Jul 29 '12 at 0:26
Tell that to notepad. –  SimpleRookie Aug 1 '12 at 19:02

Looking at the two equations, they look pretty damn similar. There must some relationships between $x$ and $2y$. Calculate $x+2y$ and $x-2y$:
$$x+2y=is$$ $$x-2y=js$$
And you have $i$ and $j$. It's easy to take if from here.